1. A train , 800 meter long is running with a speed of 78 km/hr. It crosses a tunnel in 1 minute. What is the length of the tunnel (in meters)?
1. 440 m
2. 500 m
3. 260 m
4. 430 m
Answer & Explanation Answer:- 2 Explanation :- Let length of tunnel is x meter 2. Two train each 500 m long, are running in opposite directions on parallel tracks. If their speeds are 45 km/hr and 30 km/hr respectively, the time taken by the slower train to pass the driver of the faster one is Answer & Explanation Answer:- 3 Explanation :- Relative Speed = 45 + 30 = 75 km/h = 750/36 m/s = 125/6 m/s 3. Two trains are running at 40 km/hr and 20 km/hr respectively in the same direction. If the fast train completely passes a man sitting in the slower train in 5 seconds, the length of the fast train is : Answer & Explanation Answer:- 2 Explanation :- As Trains are moving in same direction, 4. Two trains are running in opposite directions in the same speed. The length of each train is 120 meter. If they cross each other in 12 seconds, the speed of each train (in km/hr) is Answer & Explanation Answer:- 2 Explanation :- Distance covered = 120+120 = 240 m 5. A train 108 m long is moving at a speed of 50 km/hr . It crosses a train 112 m long coming from opposite direction in 6 seconds. What is the speed of the second train? Answer & Explanation Answer:- 1 Explanation :- Speed of 1st Train = 50 km/h
Distance = (800+x)meter
Time = 1 minute = 60 seconds
Speed = 78 km/hr = (78*5/18) m/s = 65/3 m/s
Distance = Speed*Time
(800 + x) = (65/3)*60
(800 + x) = 20*65
800 + x = 1300
x = 500
Therefore , the length of the tunnel = 500 meters.
1. 50 sec
2. 58 sec
3. 24 sec
4. 22 sec
Distance = Length of the smaller train
Time = Distance/Speed = 500/(125/6) = 24 s
1. 19 m
2. 27 7/9 m
3. 13 2/9 m
4. 33 m
So, Relative Speed = 40-20 = 20 km/h = 20*(5/18) = 50/9 m/sec
Length of Train= Speed * Time
Length of train = (50/9)*20 = 250/9 = 27 7/9 m
1. 42
2. 36
3. 28
4. 20
Time = 12 s
Let the speed of each train = x m/s
Therefore ,
Relative speed = x + x = 2x
Speed = Total distance/Time
2x = 240/12 = 20 m/s
x = 10 m/s
Speed of each train = 10 m/s
= 10 × 36/10 km/hr = 36 km/hr
1. 82 kmph
2. 76 kmph
3. 44 kmph
4. 58 kmph
Let the speed of Second train = x km/h
Relative Speed = (x +50) km/h = (x + 50) (5/18) m/s = (5x + 250)/18 m/s
Distance Covered = (108 + 112) = 220 m
Speed = distance / Time
(5x + 250)/18 = 220 / 6
5x + 250 = 660
5x = 410 => x = 82 km/h