1. Rahul went to a shop and bought things worth Rs. 25, out of which 30 Paise went on sales tax on taxable purchases. If the tax rate was 6%, then what was the cost of the tax free items?
1. Rs. 15
2. Rs. 12.10
3. Rs. 19.70
4. Rs. 16.80
Answer & Explanation Answer:- 3 Explanation :- Let the amount taxable purchases be Rs. x. 2. The population of a town increased from 1,75,000 to 2,62,500 in a decade. What is the average percent increase of population per year? Answer & Explanation Answer:- 3 Explanation :- Population Increased= 2,62,500 – 1,75,000=87500 3. Three candidates contested an election and received 1136, 7636 and 11628 votes respectively. What percentage of the total votes did the winning candidate get? Answer & Explanation Answer:- 1 Explanation :- Total number of votes = (1136 + 7636 + 11628) = 20400. 4. A fruit seller had some oranges. He sells 40% oranges and still has 420 oranges. How many oranges he had originally? Answer & Explanation Answer:- 2 Explanation :- Sold Oranges=40% of total oranges 5. A batsman scored 110 runs which included 3 boundaries and 8 sixes. What percent of his total score did he make by running between the wickets? Answer & Explanation Answer:- 3 Explanation :- Number of runs made by running = 110 – (3 x 4 + 8 x 6)
Then, 6% of x =30/100
x=(30/100)*(100/6)
x=5
Cost of tax free item=(25-(5+0.30))= Rs.19.70
1. 4%
2. 6%
3. 5%
4. 50%
% Increased In population=(87500/175000)*100
% Increased In population=50%
The average % increase of population=(50/10)%=5%
1. 57%
2. 50%
3. 52%
4. 60%
% of votes for winning Candidate=(11628/20400)*100=57%
1. 420
2. 700
3. 220
4. 400
Remaining oranges=60% of total oranges =420
Therefore (60/100)oranges=420
Oranges=420*100/60
Oranges=700
1. 45411 %
2. 45 %
3. 45511 %
4. 44511 %
= 110 – (60)
= 50.