1. What percentage of numbers from 1 to 70 have 1 or 9 in the unit’s digit?
1. 2023%
2. 20%
3. 21%
4. 2223%
Answer & Explanation Answer:- 2 Explanation :- Such numbers from 1 to 70 are 1, 9, 11, 19, 21, 29, 31, 39, 41, 49, 51, 59, 61, 69. 2. In an election between two candidates, one got 55% of the total valid votes, 20% of the votes were invalid. If the total number of votes was 7500, what was the number of valid votes that the other candidate got? Answer & Explanation Answer:- 2 Explanation :- Total votes = 7500 3. In a competitive examination in State A, 6% candidates got selected from the total appeared candidates. State B had an equal number of candidates appeared and 7% candidates got selected with 80 more candidates got selected than A. What was the number of candidates appeared from each State? Answer & Explanation Answer:- 4 Explanation :- In state A , Selected students =6% of total appeared candidates 4. What percent of a day is 6 hours? Answer & Explanation Answer:- 3 Total hours in day=24 5. A student has to obtain 33% of the total marks to pass. He got 125 marks and failed by 40 marks. The maximum marks are Answer & Explanation Answer:- 2 Explanation :- Student got 125 marks
Number of such number =14
percentage of numbers =(14/70)*100
=>20%
1. 2800
2. 2700
3. 2100
4. 2500
Valid votes = 80%
Total valid votes =7500*80/100
Vote for First Candidate=55% of valid votes
Vote for Second Candidate=45% of valid votes
=>(45/100)(80/100)*7500
=>2700 votes
1. 8200
2. 7500
3. 7000
4. 8000
In state B, Selected students = 7% of total appeared candidates
Differece between selected students of A & B=80
Therefore 1% of total appeared candidates=80
Total appeared candidates in A=Total appeared candidates in B= 80*100=8000
1. 6.25%
2. 20%
3. 25%
4. 12.5%
Required %age=(6/24)*100
1. 600
2. 500
3. 400
4. 300
failed by 40 marks
Minimum Passing marks required = 125 + 40 = 165
Therefore 33% of total marks=165
total marks =(165*100)/33
Total marks=500