Directions (1-4) Study the following line graph to answer these questions
Answer & Explanation 1. (4)
the average speed maintained by the train between different stations E and F 106 km in 5/4 h =((106×4) )/5 = 84.8 kmph
Similarly, average speed between F and G = 176 km
In 2h = 88 km/h
Between G and H = (110*4)/5 = 88 km/h
2.(4)
Over all average speed of the entire trip : 860 km in 11 hr 25 min
i.e. (685/137) h =(860*12)/137 = 75.3 km/h
Average speed maintained by the train between station
A and B 140 km in 12/3h = (140*3)/5 = 84 km/h
B and C 91 km in 4/3 h=91*(3/4) km/h=68.25 km/h
C and D 149 km in 103/60=(149*60)103 =86.8 km/h
D and E 88 km in 4/3 h=(88*3)/4=66 km/h
E and F = 84.8 km, FG = 88km/h, GH = 88km/h
Hence, for two stations it runs below the overall average speed
3.(3)
The train stops at station B for 3 min more
The train stops at station C for 36 sec more
The train stops at station D for 1.5 min more
The train stops at station E for 3 min more
The train stops at station F for 4.5 min more
In all the trains stops 15 min and 36 s more
The train will reach city H after departing from city A at 16h, 40 min, 36 sec i.e., 16h , 41 min approx
4.(4)
Let the distance between city H and city M be x km.
Time taken by the trains from H and A (return)
860/90 = 86/9h
Given, the trains reaches city A (return) at 2.25 am
i.e, at 26.25(hours)
The train reaches at H (return)
At = (26+25/60)-86/9= (16+31/36)h
Time taken from H to M and back
(607/36) – (192/12)= 4/3h
Since the train runs from G to H 88km/h, therefore the train runs 88km/h from city H to city M also. Also speed between city M and city H = 90kmph
x/88+x/90=4/3
x = 59 km