 # Ratio & Proportion (1)

1. Father is aged three times more than his son Sunil. After 8 years, he would be two and a half times of Sunil’s age. After further 8 years, how many times would he be of Sunil’s age?
1. 4 times
2. 4 times
3. 2 times
4. 3 times

Explanation :-

Assume that Sunil’s present age = x
Then, father’s present age = 3x + x = 4x
After 8 years, father’s age = (5/2) times of Sunils’ age
After further 8 years,
(48) = (5/2)(8)
816 540
34016
x = 8
After further 8 years,
Sunil’s age = (x + 8) + 8 = 8 + 8 + 8 = 24
Father’s age = 4x + 8 = (4*8) + 8 = 48
Father’s age/Sunil’s age = 48/24 = 2

2. Ten years ago, P was half of Q’s age. If the ratio of their present ages is 3:4, what will be the total of their present ages?
1. 45
2. 40
3. 35
4. 30

Explanation :-

Let the present age of P and Q be 3x and 4x respectively.
Ten years ago, P was half of Q in age=> 2(3x – 10) = (4x – 10)
=> 6x – 20 = 4x – 10
=> 2x = 10
=> x = 5

3. Two numbers are such that if the first is subtracted from six times the second, their difference becomes 71, and if the second be added to 7 times the first , their sum becomes 62. The two numbers are
1. 19, 7
2. 13, 7
3. 7, 13
4. 17, 3
5. None of these

Explanation :-

Let the number  be x and y
Then 6y – x = 71 and 7x + y = 62
By Solving these equations
x = 7,  y = 13

4. The sum of three numbers is 98. If the ratio of the first to second is 2 :3 and that of the second to the third is 5 : 8, then the second number is:
1. 58
2. 48
3. 30
4. 20

Explanation :-

3
(53/5) : (83/524/5
24/ 10:15:24
9815/49 30

5. The ratio of the number of boys and girls in a college is 7 : 8. If the percentage increase in the number of boys and girls be 20% and 10% respectively, what will be the new ratio?
1. 17 : 18
2. 8 : 9
3. Cannot be determined
4. 21 : 22