1. A and B walk around a circular track. A and B walk at a speed of 2 rounds per hour and 3 rounds per hour respectively. If they start at 8 a.m. from the same point in opposite directions, how many times shall they cross each other before 9.30 a.m.?
1. 5
2. 6
3. 7
4. 8
Answer & Explanation Answer:- 3 Explanation :- Speed of A = 2 rounds/hr & Speed of A = 2 rounds/hr 2. Two boys starts from the same place walking at the rate of 5 kmph and 5.5 kmph respectively in the same direction. What time will they take to be 8.5 km apart? Answer & Explanation Answer:- 1 Explanation :- Relative Speed = 5.5 – 5 = 0.5 km/h 3. In covering a distance of 30 km, Arun takes 2 hours more than Anil. If Arun doubles his speed, then he would take 1 hour less than Anil. What is Arun’s speed? Answer & Explanation Answer:- 2 Explanation :- Let Arun’s speed = x km/h 4. A Man travelled a distance of 61 km in 9 hours. He travelled partly on foot at 4 km/hr and partly on bicycle at 9 km/hr. What is the distance travelled on foot? Answer & Explanation Answer:- 3 Explanation :- Let’s assume distance covered on foot = x km. 5. Walking 6/7th of his usual speed, a man is 12 minutes too late. What is the usual time taken by him to cover that distance? Answer:- 4 Explanation :- Let the original speed = x km/minute & time = t minutes OR Distance is directly related to speed,
Relative speed = 2 + 3 = 5 rounds/hr
In 1 hour They cross each other = 5 times
In Half an hour They cross each other = 2 times
from 8 to 9:30 (1 and half hour ) they cross each other (5 + 2) = 7 times
1. 17 hr
2. 14 hr
3. 12 hr
4. 19 hr
Distance = 8.5 km
Time = Distance/Speed
Time= 8.5 / 0.5 = 17 hrs
1. 8 kmph
2. 5 kmph
3. 4 kmph
4. 7 kmph
(30/x) – 30/(2x) = 3
6x = 30 => x = 5 km/h
1. 12 km
2. 14 km
3. 16 km
4. 18 km
Therefore , Distance covered on bicycle = (61 –x) km.
Time = Distance / Speed
(x/4) + (61 – x)/ 9 = 9
(9x + 244 -4x)/36 = 9
5x + 244 = 9*36
x = 16
Therefore, Distance traveled on foot = 4(4) = 16 km
1. 1 hr 42 min
2. 1 hr
3. 2 hr
4. 1 hr 12 min
Distance (with original speed) = tx
Distance(with speed slower speed) = (t+12) (6x/7)
As Both the distances are same
tx= (t+12) (6x/7)
t = 72 minuets (1 hr 12 min)
Therefore at 6/7 the speed he will cover 7/6 the distance.
Therefore 1/6 the distance is covered in 12 min
2/6 the distance is covered in = 2*12 = 24 min
…
So, Whole Distance is covered in = 6 * 12 = 72 min