1.A is thrice as good a workman as B and takes 10 days less to do a piece of work than B takes. B alone can do the whole work in ?
1. 15 days
2. 10 days
3. 9 days
4. 8 days
5. None of these
Answer & Explanation Answer:- 1 Explanation :- Lets suppose A can complete the work in x days 2.4 men and 6 women finish a job in 8 days, while 3 men and 7 women finish it in 10 days. In how many days will 10 women working together finish it ? Answer & Explanation Answer:- 2 Explanation :- Lets suppose work done by 1 man in 1 day = x 3.10 women can complete a work in 7 days and 10 children take 14 days to complete the work. How many days will 5 women and 10 children take to complete the work? Answer & Explanation Answer:- 2 Explanation :- 10 women complete the work in 7 days 4. 5 men and 2 boys working together can do four times as much work as a man and a boy. Working capacity of man and boy is in the ratio? Answer & Explanation Answer:- 3 Explanation :- Lets suppose work done by 1 man in 1 day = x 5. A work is done by three person A,B and C. A alone takes 10 hours to complete a single product but B and C working together takes 4 hours, for the completion of the same product. If all of them worked together and completed 14 products, then how many hours have they worked? Answer & Explanation Answer:- 3 Explanation :- No. of products completed by Ain 1 Hour (1/A) = 1/10 6. Adam can do a job in 15 days, John can do the same job in 20 days. If they work together for 4 days on this job. What fraction of job is incomplete ? Answer:- 4 Explanation :- Adam’s 1 day work = 1/15
Therefore B can complete the work in 3x days
3x – x = 10
x = 5
B can complete the work in 3*5 = 15 days
1. 30 days
2. 40 days
3. 50 days
4. 60 days
5. None of these
and 1 woman’s 1 days work = y.
Then, 4x + 6y = 1/8 ——— Multiply it by 3
and 3x+7y = 1/10 ———–Multiply it by 4
we get ,
12x + 18x = 3/8
12x + 28x =4/10
By subtracting both the equations,
we get , y = 1/400
1 day work of 10 women = 10/400 = 1/40
Therefore , 10 women will finish the work in 40 days
1. 6 days
2. 7 days
3. 8 days
4. 9 days
5. None of these
5 women complete the work in 7*2 = 14 days
10 children complete the work in = 14 days
One day work of 5 women & 10 children = (1/14) + (1/14) = 2/14 = 1/7
Therefore , They complete the work in 7 days
1. 1:2
2. 1:3
3. 2:1
4. 2:3
5. None of these
work done by 1 boy in 1 day = y
Therefore , According to Question
5x + 2y = 4(x+y)
x = 2y => x/y = 2/1
Therefore , x : y = 2 : 1
1. 20 hrs
2. 28 hrs
3. 40 hrs
4. 54 hrs
5. None of these
No. of products completed by (B+C) in 1 Hour = 1/4 (Given)
(1/A) + (1/B) + (1/C) = (1/10) + (1/4) = 7/20
Therefore
In 20 hours, working together they will complete 7 products.
Thus in 40 hours they will complete 14 products
1. 1/4
2. 1/10
3. 7/15
4. 8/15
5. none of these
John’s 1 day work = 1/20
1 day work of both together = (1/15) + (1/20) = 7/60
4 day work of both together = (4*7)/60 = 7/15
Remaining work = 1 – (7/15) = 8/15