1. In how many years, Rs. 150 will produce the same interest at 6% as Rs. 800 produce in 2 years at 4½% ?

1. 4 years

2. 6 years

3. 8 years

4. 9 years

Answer & Explanation

Answer:- 3

Explanation :-

SI for Rs.150 at 6% for t years = SI for Rs.800 at 4½ % for 2 years

(150*6*t)/100 = (800*(9/2)*2)/100

150*6*t = 800*9

t = (800*9)/(150*6)

t = 8 Years

2. A sum of Rs. 2500 amounts to Rs. 3875 in 4 years at the rate of simple interest. What is the rate of interest?

1. 12.25%

2. 12%

3. 6%

4. 13.75%

Answer & Explanation

Answer:- 4

Explanation :-

P = Rs. 2500

T = 4 years

SI = 3875 – 2500 = Rs.1375

R = (SI*100)/(P*T)=(1375*100)/(2500*4)

R = 13.75%

3. What is the interest due after 40 days for Rs. 3200 at 10%

1. 35.07

2. 36.21

3. 35.52

4. 34

Answer & Explanation

Answer:- 1

Explanation :-

P = 3200

R = 10%

T = 40/365 year

SI = (P*R*T)/100

SI = (3200*10*(40/365))/100

SI = Rs. 35.07

4. What is the rate of interest at which Rs.150 becomes Rs. 220 in 10 years.

1. 11/3%

2. 14/3%

3. 12%

4. 14%

Answer & Explanation

Answer:- 2

Explanation :-

P = 150, R = ? , T = 10 years

SI = 220-150 = 70

R = (SI*100)/(P*T)

R = (70*100)/(150*10)

R = 14/3 %

5. A person invested in all Rs. 2600 at 4%, 6% and 8% per annum simple interest. At the end of the year, he got the same interest in all three cases. The money invested at 4% is:

1. Rs.2200

2. Rs.800

3. Rs.1600

4. Rs.1200

Answer & Explanation

Answer:- 4

Explanation :-

Let’s suppose the portions pf money invested be x, y and 2600 – (x + y)

Therefore,

SI for Part of money invested at 4% = SI for Part of money invested at 6% = SI for Part of money invested at 4%

(x * 4 * 1)/100 = (y * 6 * 1)/100 = [{2600 – (x + y) }* 8 * 1]/100

y/x = 4/6 = 2/3

or

y = 2/3 x

Therefore

(x * 4 * 1)/100 = [(2600 – 5/3 x) * 80/100]
52x = (7800 * 8)

=> x = 1200

Part of money invested at 4% = Rs. 1200.