1. What percentage of numbers from 1 to 70 have 1 or 9 in the unit’s digit?

1. 2023%

2. 20%

3. 21%

4. 2223%

Answer & Explanation

Answer:- 2

Explanation :-

Such numbers from 1 to 70 are 1, 9, 11, 19, 21, 29, 31, 39, 41, 49, 51, 59, 61, 69.

Number of such number =14

percentage of numbers =(14/70)*100

=>20%

2. In an election between two candidates, one got 55% of the total valid votes, 20% of the votes were invalid. If the total number of votes was 7500, what was the number of valid votes that the other candidate got?

1. 2800

2. 2700

3. 2100

4. 2500

Answer & Explanation

Answer:- 2

Explanation :-

Total votes = 7500

Valid votes = 80%

Total valid votes =7500*80/100

Vote for First Candidate=55% of valid votes

Vote for Second Candidate=45% of valid votes

=>(45/100)(80/100)*7500

=>2700 votes

3. In a competitive examination in State A, 6% candidates got selected from the total appeared candidates. State B had an equal number of candidates appeared and 7% candidates got selected with 80 more candidates got selected than A. What was the number of candidates appeared from each State?

1. 8200

2. 7500

3. 7000

4. 8000

Answer & Explanation

Answer:- 4

Explanation :-

In state A , Selected students =6% of total appeared candidates

In state B, Selected students = 7% of total appeared candidates

Differece between selected students of A & B=80

Therefore 1% of total appeared candidates=80

Total appeared candidates in A=Total appeared candidates in B= 80*100=8000

4. What percent of a day is 6 hours?

1. 6.25%

2. 20%

3. 25%

4. 12.5%

Answer & Explanation

Answer:- 3

Total hours in day=24

Required %age=(6/24)*100

5. A student has to obtain 33% of the total marks to pass. He got 125 marks and failed by 40 marks. The maximum marks are

1. 600

2. 500

3. 400

4. 300

Answer & Explanation

Answer:- 2

Explanation :-

Student got 125 marks

failed by 40 marks

Minimum Passing marks required = 125 + 40 = 165

Therefore 33% of total marks=165

total marks =(165*100)/33

Total marks=500