1. P and Q need 8 days to complete a work. Q and R need 12 days to complete the same work. But P, Q and R together can finish it in 6 days. How many days will be needed if P and R together do it?
1. 3
2. 8
3. 12
4. 4
Answer & Explanation Answer:- 2 Explanation :- (P+Q+R)’s one day work =1/6 2. P can do a work in 24 days. Q can do the same work in 9 days and R can do the same in 12 days. Q and R start the work and leave after 3 days. P finishes the remaining work in — days. Answer & Explanation Answer:- 4 Explanation :- P’s 1 day work = 1/24 3. If daily wages of a man is double to that of a woman, how many men should work for 25 days to earn Rs.14400? Given that wages for 40 women for 30 days are Rs.21600. Answer & Explanation Answer:- 3 Explanation :- Wages of 1 woman for 1 day = 21600/(40×30) 4. P, Q and R together earn Rs.1620 in 9 days. P and R can earn Rs.600 in 5 days. Q and R in 7 days can earn Rs.910. How much amount does R can earn per day? Answer & Explanation Answer:- 2 Explanation :- Money earned by (P + Q + R) in 1 day = 1620/9 = Rs. 180 5. Assume that 20 cows and 40 goats can be kept for 10 days for Rs.460. If the cost of keeping 5 goats is the same as the cost of keeping 1 cow, what will be the cost for keeping 50 cows and 30 goats for 12 days? Answer & Explanation Answer:- 1 Explanation :- Let the cost of keeping one cow for 1 day be Rs. c & keeping one goat for 1 day be Rs. g
Let (P & R)’s one day work = pr ———-(1)
(P & Q)’s one day work = 1/8 ———–(2)
(Q & R)’s one day work = 1/12 ———–(3)
By Adding (1), (2) & (3)
(2P + 2Q + 2R)’s 1 day work = (pr) + (1/8) + (1/12)
2(P + Q + R)’s 1 day work = (pr) + (1/8) + (1/12)
2*(1/6) = (pr) + 5/24
pr = (1/3) – (5/24)
pr = 1/8
Therefore P & R can complete the work in 8 days
1. 7
2. 8
3. 9
4. 10
Q’s 1 day work = 1/9
R’s 1 day work = 1/12
Work done by Q and R in 1 day = 1/9 + 1/12 = 7/36
Work done by Q and R in 3 days = 3×7/36 = 7/12
Remaining work = 1 – (7/12) = 5/12
Time taken by P to finish the remaining work = (5/12) / (1/24) = 10 days
1. 12
2. 14
3. 16
4. 18
Wages of 1 man for 1 day = (21600×2)/(40×30)
Wages of 1 man for 25 days = (21600×2×25)/(40×30)
Number of men = 14400/(21600×2×25)/(40×30) = (144×40×30)/(216×50)) = 144/9 = 16
1. Rs.40
2. Rs.70
3. Rs.90
4. Rs.100
Money earned by (P + R) in 1 day = 600/5 = Rs. 120 —(1)
Money earned by (Q + R) in 1 day = 910/7 = Rs.130 —(2)
Lets suppose Money earned by (P + Q) in 1 day = Rs. pq —(3)
Adding (1) (2) & (3)
2(P+Q+R) = 120 + 130 + pq
2(180) = 250 + pq
pq = Rs. 110
Money earned by R in 1 day = 180 – 110 = Rs. 70
1. Rs.1104
2. Rs.1000
3. Rs.934
4. Rs.1210
& keeping one goat for 1 day be Rs. g
Given that 1c = 5g
(20c +40g)*10 = Rs. 460
[(20*5g) + 40g ) *10 = Rs. 460
1000g + 400g = 460
g = 23/70 , therefore , c = 23/14
The cost for keeping 50 cows and 30 goats for 12 days =[(50*23/14) + (30*23/70)] * 12
=> (69+575)/7 = Rs.1104