1. To Finish a work, B will take three times as long as A and C together and C will take twice as long as A and B together. If the three persons A, B and C together can finish the work in 20 days , then how long will A take to finish the work alone?
1. 30 days
2. 45 days
3. 48 days
4. 60 days
5. None of these
Answer & Explanation Answer:- 3 Explanation :- Let time taken by A & C to complete the Work = x days 2. Ram takes 6 hours to type 32 pages. Shaam takes 5 hours to type 40 pages. In how many hours they will type 110 pages together ? Answer & Explanation Answer:- 3 Explanation :- Number of pages typed by Ravi in 1 hour = 32/6 = 16/3 3.7 men take 12 days to complete a job. They worked for 5 days, after 5 days 2 men left the job. In how many days 5 men will complete the job ? Answer & Explanation Answer:- 5 Explanation :- 7 Man can complete the work in 12 days 4.If A, B and C can do a job in 20, 30 and 60 days respectively. In how many days A can do the work if B and C help him on every third day ? Answer & Explanation Answer:- 2 Explanation :- Work done by A in 1 day = 1/20 5.A is twice as good as workman as B and together they finish a piece of work in 18 days. In how many days will B alone finish the work? Answer & Explanation Answer:- 2 Explanation :- Lets suppose A completes the work in x days
Therefore , Time taken by B to complete the Work = 3x days
Therefore , Work done by A, B and C in 1 day = (1/x) + (1/3x)
(1/x) + (1/3x) = 1/20
x = 80/3
Let time taken by A & B to complete the Work = y days
Therefore , Time taken by C to complete the Work = 2x days
Therefore , Work done by A, B and C in 1 day = (1/y) + (1/2y)
(1/y) + (1/3y) = 1/20
y = 30
Now ,
Work done by A, B and C in 1 day = (1/A) + (1/3x) + (1/2y) = 1/20
A = 48 days
1. 7 hours
2. 8 hours
3. 8 hours 15 min
4. 8 hours 30 mins7 hours
5. None of these
Number of pages typed by Kumar in 1 hour = 40/5 = 8
Number of pages typed by both in 1 hour =(16/3) + 8 = 40/3
Time taken by both to type 110 pages =110 * (3/40) = 8 1⁄4
1. 5 days
2. 7 days
3. 9 days
4.10 days
5. None of these
5 days work of 7 men = 5/12
Remaining Work = 1 – (5/12) = 7/12
1 man can complete the work in = 12*7 = 84
1 day work of a man = 1/84
5 day work of men = 5/84
Time taken by 5 men to complete the Remainning work = (7/12)/(5/84) = 49/5 days
1. 12 days
2. 15 days
3. 16 days
4. 18 days
5. None of these
Work done by B in 1 day = 1/30
Work done by C in 1 day = 1/60
Work done by A in 2 days = 2/20 = 1/10
Work done by A ,B & C in every third day = (1/20) + (1/30 + (1/60) = 1/10
Work completed in every 3 days = (1/10) + (1/10) = 1/5
So work completed in 15 days = 5 × 1/5 = 1
Ie, the work will be done in 15 days
1. 27 days
2. 54 days
3. 56 days
4. 68 days
5. None of these
Therefore ,B can complete the work in 2x days
A’s 1 day work = 1/x , B’s 1 day work = 1/2x
(1/x) + (1/2x) = 1/18
x = 27
A competes the work in 27 days , therefore B can complete the work in 2*27 = 54 days