# Table 65

Directions for questions 1 to 5: A team of 5 players A, B, C, D and E participated in a tournament and played four matches (1 to 4). The following table gives partial information about their individual scores and the total runs scored by the team in each match.
Each column has two values missing. These are the runs scored by the two lowest scorers in that match. None of the two missing values is more than 10% of the total runs scored in that match. Q1.What is the maximum possible percentage contribution of A in the total runs scored in the four matches?
(a) 19.7%
(b) 19.9%
(c) 20.1%
(d) 20.2%
(e) Cannot be determined

Q2.What is the maximum possible percentage contribution of E in the total runs scored in the four matches?
(a) 18.2%
(b) 19.9%
(c) 18.6%
(d) 20.2%
(e) Cannot be determined
Q3.If the absolute difference between the total runs scored by A and C in the four matches is minimum possible then what is the ratio of A and C’s total runs scored by them in the four matches.
(a) 187:189
(b) 189:187
(c) 183:187
(d) 189:188
(e) Cannot be determined
Q4.If the absolute difference between the total runs scored by A and C in the four matches is minimum possible then what is the absolute difference between total runs scored by B and E in the four matches?
(a) 32
(b) 37
(c) 35
(d) 27
(e) Cannot be determined
Q5.The players are ranked 1 to 5 on the basis of the total runs scored by them in the four matches, with the highest scorer getting Rank 1. If it is known that no two players scored the same number of total runs, how many players are there whose ranks can be exactly determined?
(a) 0
(b) 1
(c) 3
(d) 5
(e) Cannot be determined

1.Option (a)
Maximum possible runs scored by A in Match-1 = 27
Maximum possible runs scored by A in Match-3 = 19
Maximum possible percentage contribution:
(27+100+19+53)/(270+300+240+200)x100% = 199/1010×100% = 19.7%

2.Option (c)
Maximum possible runs scored by E in Match-2 = 30
Maximum possible runs scored by E in Match-4 = 20
Maximum possible percentage contribution:
(60+30+78+20)/(270+300+240+200)x100%
= 188/1010×100% = 18.6%

3.Option (b)
Maximum possible total runs scored by C in the four matches
= 27 + 30 + 110 + 20 = 187.
In such a case minimum possible total runs scored by A in the four matches = 23 + 100 + 13 + 53 = 189
Difference = 189 – 187 = 2 (minimum possible)
So Required ratio is 189:187

4.Option (b)
Maximum possible total runs scored by C in the four matches
= 27 + 30 + 110 + 20 = 187.
In such a case minimum possible total runs scored by A in the four matches
= 23 + 100 + 13 + 53 = 189.
Difference = 189 – 187 = 2 (minimum possible) Subsequently total runs scored by B in the four matches
= 88 + 65 + 19 + 52 = 224.
Also, total runs scored by E in the four matches
= 60 + 30 + 78 + 19 = 187
Absolute difference = 224 – 187 = 37

5.Option (c)
Individual ranges for total score:
A-> 189-199
B-> 218-224
C-> 182-187
D-> 223
E-> 187-188
Least total will be of C (Rank 5)
2nd least will be E (Rank 4)
Rank 3 must be of A.
It is not possible to determine the exact ranks of B and D.