Directions (Q. 1-5): Study the following table carefully and answer the questions given below:
Following table shows the percentage of marks obtained by different students in six subjects.
Q1. What are the total marks obtained by student A in all subjects together?
1) 443
2) 448
3) 456
4) 464
5) 472
Q2. What are the percentage of average marks obtained by the six students in Physics?
1) 43.6%
2) 46%
3) 48.5%
4) 49.2%
5) 51.5%
Q3. Approximately what is the overall percentage of marks obtained by student D in all the subjects together?
1) 57.4%
2) 60%
3) 59.5%
4) 61.8%
5) 62.3%
Q4. Marks obtained by student C in Biology is approximately what per cent of the marks obtained by student A in English?
1) 57%
2) 43%
3) 51%
4) 47%
5) 49%
Q5.What is the difference between the total marks obtained by ‘E’ in Physics, Chemistry and Biology together and the total marks obtained by F in the same three subjects together?
1) 9
2) 12
3) 15
4) 7
5) 6
Answer & Explanation1.2Total marks = 75 ×. 52 + 75 × .6 + 75 × .88 + 200 × .59 +120 × .65 + 150 × .68= 39 + 45 + 66 + 118 + 78 + 102 = 4482. 3Average = 75/6 (.52 + .80 + .56 + .60 + .64 + .76)= (75 * 3.88)/6= 48.5%3. 5Total marks = 45 + 54 + 42 + 142 + 66 + 84 = 433Required percentage = 433/695 × 100 = 62.3%4. 4CBio = 0.75 × 64 = 48AEng = 150 × 0.68 = 102Required percentage = 48/102 × 100 = 47%5. 1Difference = 75/100 {(64 + 76 + 60) – (76 + 64 + 48)}= 75/100 * 12 = 9