Directions for questions 1 to 5: A test paper contains 50 questions. 4 marks are awarded for every correct answer and one mark is deducted for every wrong answer. Aryan, Bunny, Chetana and Divya appeared for this test and their scores are given in the following table. Further it is also known that Divya has scored the maximum marks. Complete the following table and answer the questions that follow.
Q1.Who answered the second highest number of questions correctly (No two students answered same number of questions correctly)?
(a) Aryan
(b) Bunny
(c) Chetana
(d) Divya
(e) Cannot be determined
Q2.Who answered the maximum number of questions incorrectly?
(a) Aryan
(b) Bunny
(c) Chetana
(d) Divya
(e) Cannot be determined
Q3.If all the questions attempted by Divya are not correct, then which of the following can be the score of Divya?
(a) 189
(b) 188
(c) 196
(d) 191
(e) Cannot be determined
Q4.If the average score of all the four students is a multiple of 5, then what is the total number of correct answers by all the four?
(a) 157
(b) 167
(c) 140
(d) 146
(e) Cannot be determined
Q5.If Divya got 4th rank among the four students with the maximum possible marks then what could be the maximum number of questions she attempted?
(a) 15
(b) 47
(c) 21
(d) 46
(e) Cannot be determined
Answer & ExplanationDirections for questions 1 to 5: Following is the complete chart:
1.Choice (c)
2.Choice (a)
3.Choice (d)
Since Divya scored maximum marks, hence his score is more than 187, but note that she cannot score all the scores more than 187, there are only some scores which she can score.
Thus only a score of 191 is possible.
4.Choice (a)
For being the average a multiple of 5 Divya must attempt 48 questions and also all of them must be correct. So total correct questions by four becomes = 16 + 46 + 47 + 48 = 157.
5.Choice (d)
In order to get maximum marks with lowest rank,Divya must score 59 with maximum attempts. Which could be realized by the equation 4x – y = 59. Which satisfies for x = 21 and y = 25. Hence the maximum question that he could attempt is 46.
